{"title":"The spherical maximal operators on hyperbolic spaces","authors":"Peng Chen, Minxing Shen, Yunxiang Wang, Lixin Yan","doi":"arxiv-2408.02180","DOIUrl":null,"url":null,"abstract":"In this article we investigate $L^p$ boundedness of the spherical maximal\noperator $\\mathfrak{m}^\\alpha$ of (complex) order $\\alpha$ on the\n$n$-dimensional hyperbolic space $\\mathbb{H}^n$, which was introduced and\nstudied by Kohen [13]. We prove that when $n\\geq 2$, for $\\alpha\\in\\mathbb{R}$\nand $1<p<\\infty$, if \\begin{eqnarray*}\n\\|\\mathfrak{m}^\\alpha(f)\\|_{L^p(\\mathbb{H}^n)}\\leq C\\|f\\|_{L^p(\\mathbb{H}^n)},\n\\end{eqnarray*} then we must have $\\alpha>1-n+n/p$ for $1<p\\leq 2$; or\n$\\alpha\\geq \\max\\{1/p-(n-1)/2,(1-n)/p\\}$ for $2<p<\\infty$. Furthermore, we\nimprove the result of Kohen [13, Theorem 3] by showing that\n$\\mathfrak{m}^\\alpha$ is bounded on $L^p(\\mathbb{H}^n)$ provided that\n$\\mathop{\\mathrm{Re}} \\alpha> \\max \\{{(2-n)/p}-{1/(p p_n)}, \\ {(2-n)/p} -\n(p-2)/ [p p_n(p_n-2) ] \\} $ for $2\\leq p\\leq \\infty$, with $p_n=2(n+1)/(n-1)$\nfor $n\\geq 3$ and $p_n=4$ for $n=2$.","PeriodicalId":501036,"journal":{"name":"arXiv - MATH - Functional Analysis","volume":"12 1","pages":""},"PeriodicalIF":0.0000,"publicationDate":"2024-08-05","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":null,"platform":"Semanticscholar","paperid":null,"PeriodicalName":"arXiv - MATH - Functional Analysis","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/arxiv-2408.02180","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 0
Abstract
In this article we investigate $L^p$ boundedness of the spherical maximal
operator $\mathfrak{m}^\alpha$ of (complex) order $\alpha$ on the
$n$-dimensional hyperbolic space $\mathbb{H}^n$, which was introduced and
studied by Kohen [13]. We prove that when $n\geq 2$, for $\alpha\in\mathbb{R}$
and $1
1-n+n/p$ for $1
\max \{{(2-n)/p}-{1/(p p_n)}, \ {(2-n)/p} -
(p-2)/ [p p_n(p_n-2) ] \} $ for $2\leq p\leq \infty$, with $p_n=2(n+1)/(n-1)$
for $n\geq 3$ and $p_n=4$ for $n=2$.