Congruences for class numbers of $$\mathbb {Q}(\sqrt{\pm 2p})$$ when $$p\equiv 3$$ $$(\text {mod }4)$$ is prime

Jigu Kim, Yoshinori Mizuno
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引用次数: 0

Abstract

For a prime \(p\equiv 3\) \((\text {mod }4)\), let \(h(-8p)\) and h(8p) be the class numbers of \(\mathbb {Q}(\sqrt{-2p})\) and \(\mathbb {Q}(\sqrt{2p})\), respectively. Let \(\Psi (\xi )\) be the Hirzebruch sum of a quadratic irrational \(\xi \). We show that \(h(-8p)\equiv h(8p)\Big (\Psi (2\sqrt{2p})/3-\Psi (\frac{1+\sqrt{2p}}{2})/3\Big )\) \((\text {mod }16)\). Also, we show that \(h(-8p)\equiv 2\,h(8p)\Psi (2\sqrt{2p})/3\) \((\text {mod }8)\) if \(p\equiv 3\) \((\text {mod }8)\), and \(h(-8p)\equiv \big (2\,h(8p)\Psi (2\sqrt{2p})/3\big )+4\) \((\text {mod }8)\) if \(p\equiv 7\) \((\text {mod }8)\).

当 $$p\equiv 3$$$(\text {mod }4)$$ 是素数时,$$mathbb {Q}(\sqrt\{pm 2p})$$的类数的协整关系
对于一个质数(((\text {mod }4)),让(h(-8p))和(h(8p))分别是(\mathbb {Q}(\sqrt{-2p})\) 和(\mathbb {Q}(\sqrt{2p})\) 的类数。让 \(\Psi (\xi )\) 是二次无理数 \(\xi \) 的希尔泽布吕赫和。我们证明了(h(-8p)equiv h(8p)\Big (\Psi (2\sqrt{2p})/3-\Psi (\frac{1+\sqrt{2p}}{2})/3\Big )\)\(\text {mod }16)\).另外,我们还证明了(h(-8p)equiv 2\,h(8p)\Psi (2\sqrt{2p})/3\)\如果 \(pequiv 3\) \((\text{mod }8)\),並且 \(h(-8p)equiv \big (2\,h(8p)\Psi (2\sqrt{2p})/3\big )+4\)\((\text {mod }8)\) if \(p\equiv 7\) \((\text {mod }8)\).
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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