Modular differential equations and algebraic systems

Hicham Saber, Abdellah Sebbar
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Abstract

This paper investigates the modular differential equation \(y''+sE_4y=0\) on the upper half-plane \({{\mathbb {H}}}\), where \(E_4\) is the weight 4 Eisenstein series and s is a complex parameter. This is equivalent to studying the Schwarz differential equation \(\{h,\tau \}=2sE_4\), where the unknown h is a meromorphic function on \({{\mathbb {H}}}\). On the other hand, such a solution h must satisfy \(h(\gamma \tau )=\varrho (\gamma )h(\tau )\) for \(\tau \in {{\mathbb {H}}}\), \(\gamma \in {\text{ SL}_2({{\mathbb {Z}}})}\) and \(\varrho \) being a \(2-\)dimensional complex representation of \({\text{ SL}_2({{\mathbb {Z}}})}\). Moreover, in order for h to be meromorphic or to have logarithmic singularities at the \({\text{ SL}_2({{\mathbb {Z}}})}\)-cusps of \({{\mathbb {H}}}\), it is necessary to have \(s=\pi ^2r^2\) with r being a rational number. For \(r=m/n\) in reduced form, it turns out that \(\varrho \) is irreducible with finite image if and only if \(2\le n\le 5\) and in this case h is a modular function for the genus zero torsion-free principal congruence group \({\Gamma }(n)\), while\(\varrho \) is reducible if and only if \(n=6\). By Solving an explicit algebraic system, we prove that solutions for any \(r=m/n\) can be built from a solution corresponding to \(r=1/n\), for \(2\le n\le 6\), by integrating certain weight 2 meromorphic modular forms. Together with the earlier work by the authors for r being an integer [20], this provides the solutions to the above-mentioned differential equations for all \(r=m/n\) with \(1\le n\le 6\).

模微分方程和代数系统
本文研究了上半平面 \({{\mathbb {H}}\) 上的模微分方程 (y'''+sE_4y=0\),其中 \(E_4\) 是权 4 爱森斯坦数列,s 是复参数。这等同于研究施瓦茨微分方程(\{h,\tau \}=2sE_4\ ),其中未知数 h 是 \({{mathbb {H}}\) 上的一个离散函数。)另一方面,这样的解 h 必须满足 \(\tau \in {{\mathbb {H}}) =\varrho (\gamma )h(\tau )\、\(\gamma)在{text{ SL}_2({{\mathbb {Z}})}中,而(\varrho)是\({text{ SL}_2({{\mathbb {Z}})}的一个(2-/)维复数表示。)此外,为了使 h 成为 meromorphic 或在\({\text{ SL}_2({{\mathbb {Z}}})}的\({\mathbb {H}})-cusps处有对数奇点,必须有 \(s=\pi ^2r^2\),其中 r 是有理数。对于还原形式的 \(r=m/n\) 来说,如果并且只有当 \(2\le n\le 5\) 并且在这种情况下 h 是零属无扭主全等群 \({\Gamma }(n)\) 的模函数时, \(\varrho\) 才是不可还原的,并且具有有限的像,而如果并且只有当 \(n=6\) 时, \(\varrho\) 才是可还原的。通过求解一个显式代数系统,我们证明了对于任何(r=m/n\ )的解都可以通过积分某些权重为2的同态模形式,从对应于(r=1/n\ )的解建立起来,对于(2\le n\le 6\ )。加上作者早先针对 r 为整数的工作[20],这就为所有 \(r=m/n\) with \(1\le n\le 6\) 的上述微分方程提供了解。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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