Convexity of near-optimal orthogonal-pair-free sets on the unit sphere

Apurva Mudgal
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Abstract

A subset $S$ of the unit sphere $\mathbb{S}^2$ is called orthogonal-pair-free if and only if there do not exist two distinct points $u, v \in S$ at distance $\frac{\pi}{2}$ from each other. Witsenhausen \cite{witsenhausen} asked the following question: {\it What is the least upper bound $\alpha_3$ on the Lesbegue measure of any measurable orthogonal-pair-free subset of $\mathbb{S}^2$?} We prove the following result in this paper: Let $\mathcal{A}$ be the collection of all orthogonal-pair-free sets $S$ such that $S$ consists of a finite number of mutually disjoint convex sets. Then, $\alpha_3 = \limsup_{S \in \mathcal{A}} \mu(S)$. Thus, if the double cap conjecture \cite{kalai1} is not true, there is a set in $\mathcal{A}$ with measure strictly greater than the measure of the double cap.
单位球面上近优无正交对集合的凸性
单位球 $\mathbb{S}^2$ 的子集 $S$ 如果且仅当 S$ 中不存在两个相距$\frac{\pi}{2}$的不同点 $u,v,则称为无正交对。维森豪森(Witsenhausen)提出了下面的问题:{it在$mathbb{S}^2$的任何可度量的无正交对子集的勒贝格度量上,$alpha_3$的最小上限是多少?}我们在本文中证明了以下结果:让 $\mathcal{A}$ 是所有无正交对集合 $S$ 的集合,使得 $S$ 由有限个互不相交的凸集组成。那么,$alpha_3 =\limsup_{S \in \mathcal{A}}\mu(S)$。因此,如果双帽猜想(double cap conjecture)不成立,那么在 $\mathcal{A}$ 中存在一个度量严格大于双帽度量的集合。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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