Holomorphic functions on the disk with infinitely many zeros

Sebastiano Boscardin
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Abstract

Suppose that $\phi(z)=\sum\_{n=1}^\infty d\_nz^n$ is a series with radius of convergence greater than 1 and suppose that $d\_n$ are real numbers such that $\phi(1)\neq0$. We prove that for any integer $a$ greater than $1$, the complex variable function $$ f(z)=\sum\_{n=0}^{\infty}\phi(z^{a^n})=\phi(z)+\phi(z^a)+\phi(z^{a^2})+\phi(z^{a^3})+\cdots $$ has infinitely many zeros on the unit disk. It even takes every complex value in every disk centered in any point of the boundary.
圆盘上有无穷多个零的全纯函数
假设$\phi(z)=\sum\_{n=1}^\infty d\_nz^n$是收敛半径大于1的级数,假设$d\_n$是实数,使得$\phi(1)\neq0$。证明了对于任意大于$1$的整数$a$,复变函数$$ f(z)=\sum\_{n=0}^{\infty}\phi(z^{a^n})=\phi(z)+\phi(z^a)+\phi(z^{a^2})+\phi(z^{a^3})+\cdots $$在单位圆盘上有无穷多个零。它甚至取以边界上任意一点为中心的每个圆盘上的每一个复值。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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