A Diophantine equation including Fibonacci and Fibonomial coefficients

IF 0.7 Q2 MATHEMATICS
Nurettin IRMAK
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Abstract

In this paper, we solve the equation \begin{equation*} \sum_{k=0}^{m} {{2m+1}\brack{k}}_{F}\pm F_{t}=F_{n}, \end{equation*}% under weak assumptions. Here, $F_n$ is $n^{th}$ Fibonacci number and ${{.}\brack {.}}_{F}$ denotes Fibonomial coefficient.
一个丢番图方程,包括斐波那契系数和斐波那契系数
本文对该方程进行了求解 \begin{equation*} \sum_{k=0}^{m} {{2m+1}\brack{k}}_{F}\pm F_{t}=F_{n}, \end{equation*}% under weak assumptions. Here, $F_n$ is $n^{th}$ Fibonacci number and ${{.}\brack {.}}_{F}$ denotes Fibonomial coefficient.
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