Bits through queues

V. Anantharam, S. Verdú
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引用次数: 316

Abstract

Considers the following simple communication channel model: an error-free bit pipe leading to a buffer modeled by a single-server queue whose "packets" or "customers" are single bits. If the service rate is /spl mu/ bits/sec, common wisdom would indicate that the Shannon capacity of this communication link is /spl mu/ bits/sec. As we show in this paper, that intuition is wrong: the answer is actually higher than /spl mu/ bits/sec. How could we possibly transmit information at a rate faster than the service rate? After all, overdriving the queue with an arrival rate higher than p will not do, as the queue will become unstable and its output rate will not be higher than /spl mu/. The capacity is higher than /spl mu/ because information can be encoded into the arrival epochs. A simpler and more fundamental problem, namely the Shannon capacity of the single-server queue, is also considered.<>
通过队列的比特
考虑以下简单的通信通道模型:一个无错误的位管道通向一个由单服务器队列建模的缓冲区,该队列的“数据包”或“客户”是单个位。如果服务速率为/spl mu/ bits/sec,一般认为该通信链路的香农容量为/spl mu/ bits/sec。正如我们在本文中所展示的,这种直觉是错误的:答案实际上高于/spl mu/ bits/sec。我们怎么可能以比服务率更快的速度传递信息呢?毕竟,到达率高于p的队列不能超载,因为队列将变得不稳定,其输出率不会高于/spl mu/。容量高于/spl mu/,因为信息可以被编码到到达epoch中。本文还考虑了一个更简单、更基本的问题,即单服务器队列的香农容量。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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