Chaining with overlaps revisited

V. Mäkinen, Kristoffer Sahlin
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引用次数: 12

Abstract

Chaining algorithms aim to form a semi-global alignment of two sequences based on a set of anchoring local alignments as input. Depending on the optimization criteria and the exact definition of a chain, there are several $O(n \log n)$ time algorithms to solve this problem optimally, where $n$ is the number of input anchors. In this paper, we focus on a formulation allowing the anchors to overlap in a chain. This formulation was studied by Shibuya and Kurochin (WABI 2003), but their algorithm comes with no proof of correctness. We revisit and modify their algorithm to consider a strict definition of precedence relation on anchors, adding the required derivation to convince on the correctness of the resulting algorithm that runs in $O(n \log^2 n)$ time on anchors formed by exact matches. With the more relaxed definition of precedence relation considered by Shibuya and Kurochin or when anchors are non-nested such as matches of uniform length ($k$-mers), the algorithm takes $O(n \log n)$ time. We also establish a connection between chaining with overlaps to the widely studied longest common subsequence (LCS) problem.
重复链接
链接算法的目标是基于一组锚定的局部对齐作为输入,形成两个序列的半全局对齐。根据优化标准和链的确切定义,有几个$O(n \log n)$ time算法可以最优地解决这个问题,其中$n$是输入锚点的数量。在本文中,我们重点研究了一种允许锚点在链中重叠的配方。Shibuya和Kurochin (wai 2003)研究了这个公式,但他们的算法没有证明其正确性。我们重新审视并修改了他们的算法,以考虑锚点优先关系的严格定义,并添加了必要的推导,以确保结果算法的正确性,该算法在精确匹配形成的锚点上运行的时间为$O(n \log^2 n)$。Shibuya和Kurochin考虑了更宽松的优先关系定义,或者当锚点是非嵌套的,例如均匀长度($k$-mers)的匹配时,该算法需要$O(n \log n)$时间。我们还建立了链接与广泛研究的最长公共子序列(LCS)问题之间的联系。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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