{"title":"Secret-key generation with correlated sources and noisy channels","authors":"A. Khisti, S. Diggavi, G. Wornell","doi":"10.1109/ISIT.2008.4595138","DOIUrl":null,"url":null,"abstract":"A joint-source-channel setup for secret-key generation between remote terminals is considered. The sender communicates to the receiver over a discrete memoryless wiretap channel and the sender and receiver observe a pair of correlated discrete memoryless sources. Lower and upper bounds for the secret-key rate are presented and shown to coincide for the case when the underlying channel is a reversely degraded parallel channel. Our setup also provides an operational significance to the rate-equivocation tradeoff of the wiretap channel, and this is illustrated in detail for the Gaussian case.","PeriodicalId":194674,"journal":{"name":"2008 IEEE International Symposium on Information Theory","volume":"115 1","pages":"0"},"PeriodicalIF":0.0000,"publicationDate":"2008-07-06","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"42","resultStr":null,"platform":"Semanticscholar","paperid":null,"PeriodicalName":"2008 IEEE International Symposium on Information Theory","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.1109/ISIT.2008.4595138","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 42
Abstract
A joint-source-channel setup for secret-key generation between remote terminals is considered. The sender communicates to the receiver over a discrete memoryless wiretap channel and the sender and receiver observe a pair of correlated discrete memoryless sources. Lower and upper bounds for the secret-key rate are presented and shown to coincide for the case when the underlying channel is a reversely degraded parallel channel. Our setup also provides an operational significance to the rate-equivocation tradeoff of the wiretap channel, and this is illustrated in detail for the Gaussian case.