Analytical bounds on broadcast with hitch-hiking in wireless ad-hoc networks

G. Călinescu
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Abstract

Recently, there have been papers indicating that the maximal ratio combiner device can result in energy savings in wireless ad hoc networks by using hitch-hiking. We study the min-energy broadcast with hitch-hiking problem, an idealized version of broadcast using hitch-hiking, a problem studied experimentally in the INFOCOM 2004 paper of Agarwal et al. min-energy broadcast with hitch-hiking captures the maximum savings one can achieve in broadcasting using maximal ratio combiners. We show that the optimum of the classical min-energy broadcast problem is at most O(log2 n) times the optimum of min-energy broadcast with hitch-hiking, where n is the number of nodes in the networks. We show that this bound is tight up to a constant. In the special case when the nodes are on a line and the power requirement for node u to reach node v is d(u,v)K where d(u,v) the Euclidean distance between u and v and K is the signal attenuation exponent, which is assumed to be in between 2 and 5, we show that the optimum of the min-energy broadcast problem is at most a constant times optimum of min-energy broadcast with hitch-hiking. We also show that min-energy broadcast with hitch-hiking is NP-Hard, and present approximation algorithms. A formal definition of min-energy broadcast with hitch-hiking is given below. The input consists of a complete directed graph G = (V, E) with power requirement function c: E rarr R +, and a source s isin V. The output consists of a permutation T = < v1, v2,...., vn > of V with v1 = s and power assignment p(v) of every vertex v. For every 1 les i < j les n, define q(viv j) = p(vi)/c(vivj). An output is feasible if for every j > 1 we have Sigman i=1 p(vi)
无线自组织网络中搭便车广播的解析界
近年来,已有研究表明,最大比值组合装置可以通过搭便车的方式实现无线自组织网络的节能。我们研究了搭便车问题的最小能量广播,这是搭便车广播的理想版本,Agarwal等人在INFOCOM 2004的论文中实验研究了这个问题。搭便车的最小能量广播捕获了使用最大比例组合器在广播中可以实现的最大节省。我们证明了经典最小能量广播问题的最优值至多是搭便车最小能量广播最优值的O(log2 n)倍,其中n为网络中的节点数。我们证明了这个边界紧到一个常数。在节点在一条线上,节点u到达节点v所需功率为d(u,v)K的特殊情况下,其中u与v之间的欧氏距离d(u,v)和K为信号衰减指数,假设在2 ~ 5之间,我们证明了最小能量广播问题的最优不超过搭便车最小能量广播的常数倍最优。我们还证明了搭便车的最小能量广播是NP-Hard的,并给出了近似算法。下面给出了搭便车最小能量广播的正式定义。输入由一个具有功率需求函数c: E rarr R +的完全有向图G = (V, E)和一个源s isin V组成,输出由一个排列T = < v1, v2,....组成, vn > V, v1 = s,每个顶点V的幂赋值p(V),对于每1个顶点i < j,定义q(viv j) = p(vi)/c(vivj)。一个输出是可行的,如果对于每一个j > 1,我们有Sigman i= 1p (vi)
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