Sum-Capacity Achieving Schemes of a 2-User Gaussian Multiple-Access Channel with 1-bit ADC

Sejuti Banik, Md Hasan Rahman, M. Ranjbar, N. Tran, K. Pham
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Abstract

In this paper, we investigate the fundamentals of a static 2-user Gaussian multiple-access channel (MAC) with 1-bit analog-to-digital-converter (ADC) being equipped at the base station. To shed new light on the characteristics of sum-capacity achieving schemes, we first consider the 1-bit MAC as a single-user channel that is affected by additive white Gaussian noise (AWGN) and a fixed yet unknown interference from the other user. By examining the Kuhn-Tucker condition (KTC) for an input signal to be optimal, we demonstrate that the capacity-achieving signal of this single-user channel must have a bounded amplitude. Based on this characteristic, Dubin's theorem on extreme points of convex sets is exploited to show that the sum-capacity achieving signals of the considered MAC are discrete, with each signal having at most five mass points. In the case of equal power allocation between the two users, we establish an upper bound on the total sum-rate. We then show that the upper bound is achievable by a simple scheme in which the first user employs binary phase shift keying (BPSK) while the second user uses π/2-BPSK. Therefore, this scheme achieves one of the optimal points in the capacity region of the static 2-user 1-bit MAC. Our results show that the proposed simple scheme greatly outperforms PSK-based signaling schemes that are sum-capacity achieving in the fading 2-user 1-bit MAC.
基于1位ADC的2用户高斯多址信道和容量实现方案
在本文中,我们研究了静态2用户高斯多址信道(MAC)的基本原理,该信道在基站上配备了1位模数转换器(ADC)。为了阐明和容量实现方案的特性,我们首先将1位MAC视为受加性高斯白噪声(AWGN)和来自其他用户的固定但未知干扰影响的单用户信道。通过检验最优输入信号的库恩-塔克条件(KTC),我们证明了该单用户信道的容量实现信号必须具有有界的幅度。基于这一特点,利用凸集极值点的Dubin定理,证明了所考虑的MAC的和容量实现信号是离散的,每个信号最多有五个质量点。在两个用户之间的功率分配相等的情况下,我们建立了总和率的上界。然后,我们证明了上界可以通过一个简单的方案实现,其中第一个用户使用二进制相移键控(BPSK),而第二个用户使用π/2-BPSK。因此,该方案实现了静态2用户1位MAC容量区域的最优点之一。我们的结果表明,该简单方案大大优于基于psk的信令方案,这些信令方案在衰落的2用户1位MAC中实现和容量。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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