Some properties of meromorphic solutions of higher order linear difference equations

B. Belaïdi, Yamina Benkarouba
{"title":"Some properties of meromorphic solutions of higher order linear difference equations","authors":"B. Belaïdi, Yamina Benkarouba","doi":"10.5937/spsunp1902075x","DOIUrl":null,"url":null,"abstract":"In this paper, we investigate the growth of solutions of the linear difference equations Ak(z) f (z+ ck)+Ak−1(z) f (z+ ck−1)+ · · ·+A1(z) f (z+ c1)+A0(z) f (z) = 0, Ak(z) f (z+ ck)+Ak−1(z) f (z+ ck−1)+ · · ·+A1(z) f (z+ c1)+A0(z) f (z) = F(z), where Ak(z), · · · ,A0(z), F(z)(̸≡ 0) are entire functions and ck, · · · ,c1 are distinct non-zero complex numbers. We extend some precedent results due to Liu and Mao [15].","PeriodicalId":394770,"journal":{"name":"Scientific Publications of the State University of Novi Pazar Series A: Applied Mathematics, Informatics and mechanics","volume":"63 1","pages":"0"},"PeriodicalIF":0.0000,"publicationDate":"1900-01-01","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"5","resultStr":null,"platform":"Semanticscholar","paperid":null,"PeriodicalName":"Scientific Publications of the State University of Novi Pazar Series A: Applied Mathematics, Informatics and mechanics","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.5937/spsunp1902075x","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 5

Abstract

In this paper, we investigate the growth of solutions of the linear difference equations Ak(z) f (z+ ck)+Ak−1(z) f (z+ ck−1)+ · · ·+A1(z) f (z+ c1)+A0(z) f (z) = 0, Ak(z) f (z+ ck)+Ak−1(z) f (z+ ck−1)+ · · ·+A1(z) f (z+ c1)+A0(z) f (z) = F(z), where Ak(z), · · · ,A0(z), F(z)(̸≡ 0) are entire functions and ck, · · · ,c1 are distinct non-zero complex numbers. We extend some precedent results due to Liu and Mao [15].
高阶线性差分方程亚纯解的一些性质
本文研究了线性差分方程Ak(z) f (z+ ck)+Ak−1(z) f (z+ ck−1)+···+A1(z) f (z+ c1)+A0(z) f (z) = 0, Ak(z) f (z+ ck)+Ak−1(z) f (z+ ck−1)+···+A1(z) f (z) f (z) = f (z)的解的增长,其中Ak(z)、···、A0(z) f (z)(c)≡0)是整函数,ck、···、c1是不同的非零复数。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
求助全文
约1分钟内获得全文 求助全文
来源期刊
自引率
0.00%
发文量
0
×
引用
GB/T 7714-2015
复制
MLA
复制
APA
复制
导出至
BibTeX EndNote RefMan NoteFirst NoteExpress
×
提示
您的信息不完整,为了账户安全,请先补充。
现在去补充
×
提示
您因"违规操作"
具体请查看互助需知
我知道了
×
提示
确定
请完成安全验证×
copy
已复制链接
快去分享给好友吧!
我知道了
右上角分享
点击右上角分享
0
联系我们:info@booksci.cn Book学术提供免费学术资源搜索服务,方便国内外学者检索中英文文献。致力于提供最便捷和优质的服务体验。 Copyright © 2023 布克学术 All rights reserved.
京ICP备2023020795号-1
ghs 京公网安备 11010802042870号
Book学术文献互助
Book学术文献互助群
群 号:481959085
Book学术官方微信