Efficient exact paths for dyck and semi-dyck labeled path reachability (extended abstract)

P. Bradford
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引用次数: 8

Abstract

Consider any two vertices in a weighted digraph. The exact path length problem is to determine if there is a path of a given fixed cost between these vertices. This paper focuses on the exact path problem for costs −1,0 or +1 between all pairs of vertices. This special case is also restricted to original edge weights from {−1, +1}. In this special case, this paper gives an O(nω log2 n) exact path solution, where ω is the best exponent for matrix multiplication. Basic variations of this algorithm determine which pairs of digraph nodes have Dyck or semi-Dyck labeled paths between them, assuming two terminals or parenthesis. Therefore, determining reachability for Dyck or semi-Dyck labeled paths costs O(nω log2 n). Both the exact path and labeled path solutions can be improved by poly-log factors, but these improvements are not given here. To find Dyck or semi-Dyck reachability in a labeled digraph, each edge has a single symbol on it. A path label is made by concatenating all symbols along the path. Cycles are allowed without any repeated edges. These paths have the same number of balanced parenthesizations (semi-Dyck languages) or have an equal numbers of matching symbols (Dyck languages). The exact path length problem has many applications. These applications include the labeled path problems given here, which in turn, have many applications.
dyck和半dyck标记路径可达性的有效精确路径(扩展抽象)
考虑一个加权有向图中的任意两个顶点。确切的路径长度问题是确定这些顶点之间是否存在给定固定代价的路径。本文主要研究所有顶点对之间代价为−1,0或+1的精确路径问题。这种特殊情况也仅限于{−1,+1}的原始边权值。在这种特殊情况下,本文给出了一个O(nω log2 n)的精确路径解,其中ω是矩阵乘法的最佳指数。该算法的基本变体确定有向图节点的哪些对之间有Dyck或半Dyck标记路径,假设有两个终端或括号。因此,确定Dyck或半Dyck标记路径的可达性需要花费O(nω log2 n)。精确路径和标记路径的解都可以通过多对数因子来改进,但这里没有给出这些改进。要在标记有向图中找到Dyck或半Dyck可达性,每条边上都有一个符号。路径标签是通过连接路径上的所有符号来生成的。允许没有任何重复边的循环。这些路径具有相同数量的平衡括号(半戴克语言)或具有相同数量的匹配符号(戴克语言)。精确路径长度问题有许多应用。这些应用包括这里给出的标记路径问题,这些问题又有许多应用。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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