Imperfect random sources and discrete controlled processes

David Lichtenstein, N. Linial, M. Saks
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引用次数: 10

Abstract

We consider a simple model for a class of discrete control processes, motivated in part by recent work about the behavior of imperfect random sources in computer algorithms. The process produces a string of characters from {0, 1} of length n and is a “success” or “failure” depending on whether the string produced belongs to a prespecified set L. In an uninfluenced process each character is chosen by a fair coin toss, and hence the probability of success is |L|/2n. We are interested in the effect on the probability of success in the presence of a player (controller) who can intervene in the process by specifying the value of certain characters in the string. We answer the following questions in both worst and average case: (1) how much can the player increase the probability of success given a fixed number of interventions? (2) in terms of |L| what is the expected number of interventions needed to guarantee success? In particular our results imply that if |L|/2n = 1/w(n) where w(n) tends to infinity with n (so the probability of success with no interventions is o(1)) then with &Ogr;(√nlogw(n)) interventions the probability of success is 1-o(1). Our main results and the proof techniques are related to a well-known theorem of Kruskal, Katona, and Harper in extremal set theory.
不完全随机源和离散控制过程
我们考虑一类离散控制过程的简单模型,其部分动机是最近关于计算机算法中不完美随机源的行为的工作。该过程从{0,1}生成一个长度为n的字符串,是“成功”还是“失败”取决于生成的字符串是否属于预先指定的集合L。在一个不受影响的过程中,每个字符都是通过公平投掷硬币来选择的,因此成功的概率为|L|/2n。我们感兴趣的是玩家(控制器)的存在对成功概率的影响,玩家(控制器)可以通过指定字符串中某些字符的值来干预这个过程。我们在最坏情况和一般情况下都回答以下问题:(1)给定固定数量的干预,玩家能增加多少成功概率?(2)从L的角度来看,保证成功所需的干预措施的预期数量是多少?特别是,我们的结果表明,如果|L|/2n = 1/w(n),其中w(n)随着n趋于无穷(因此不干预的成功概率为0(1)),那么有&Ogr;(√nlogw(n))干预,成功概率为1- 0(1)。我们的主要结果和证明技术与极值集论中Kruskal、Katona和Harper的一个著名定理有关。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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