On discrete alphabets for the two-user Gaussian interference channel with one receiver lacking knowledge of the interfering codebook

Alex Dytso, Daniela Tuninetti, N. Devroye
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引用次数: 12

Abstract

In multi-user information theory it is often assumed that every node in the network possesses all codebooks used in the network. This assumption is however impractical in distributed ad-hoc and cognitive networks. This work considers the two-user Gaussian Interference Channel with one Oblivious Receiver (G-IC-OR), i.e., one receiver lacks knowledge of the interfering cookbook while the other receiver knows both codebooks. We ask whether, and if so how much, the channel capacity of the G-IC-OR is reduced compared to that of the classical G-IC where both receivers know all codebooks. Intuitively, the oblivious receiver should not be able to jointly decode its intended message along with the unintended interfering message whose codebook is unavailable. We demonstrate that in strong and very strong interference, where joint decoding is capacity achieving for the classical G-IC, lack of codebook knowledge does not reduce performance in terms of generalized degrees of freedom (gDoF). Moreover, we show that the sum-capacity of the symmetric G-IC-OR is to within O(log(log(SNR))) of that of the classical G-IC. The key novelty of the proposed achievable scheme is the use of a discrete input alphabet for the non-oblivious transmitter, whose cardinality is appropriately chosen as a function of SNR.
缺乏干扰码本知识的双用户高斯干扰信道的离散字母
在多用户信息理论中,通常假设网络中的每个节点都拥有网络中使用的所有码本。然而,这种假设在分布式ad-hoc和认知网络中是不切实际的。这项工作考虑了具有一个遗忘接收器(G-IC-OR)的双用户高斯干扰信道,即一个接收器缺乏干扰食谱的知识,而另一个接收器知道两个码本。我们的问题是,与两个接收器都知道所有码本的经典G-IC相比,G-IC- or的信道容量是否减少,如果减少,减少了多少。直观地说,不经意的接收者不应该能够将其预期的消息与码本不可用的意外干扰消息联合解码。我们证明,在强和非常强的干扰中,联合解码是实现经典G-IC的能力,缺乏码本知识不会降低广义自由度(gof)的性能。此外,我们还证明了对称G-IC- or的和容量小于经典G-IC的0 (log(log(SNR)))。提出的可实现方案的关键新颖之处在于对非遗忘发射机使用离散输入字母表,其基数被适当地选择为信噪比的函数。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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