Noisy Guesses

N. Merhav
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Abstract

We consider the problem of guessing a random, finite–alphabet, secret n–vector, where the guesses are transmitted via a noisy channel. We provide a single–letter formula for the best achievable exponential growth rate of the ρ–th moment of the number of guesses, as a function of n. This formula exhibits a fairly clear insight concerning the penalty due to the noise. We describe two different randomized schemes that achieve the optimal guessing exponent. One of them is fully universal in the sense of being independent of source (that governs the vector to be guessed), the channel (that corrupts the guesses), and the moment power ρ. Interestingly, it turns out that, in general, the optimal guessing exponent function exhibits a phase transition when it is examined either as a function of the channel parameters, or as a function of ρ: as long as the channel is not too distant (in a certain sense to be defined precisely) from the identity channel (i.e., the clean channel), or equivalently, as long ρ is larger than a certain critical value, ρc, there is no penalty at all in the guessing exponent, compared to the case of noiseless guessing.
嘈杂的猜测
我们考虑猜测一个随机,有限字母,秘密n向量的问题,其中猜测是通过噪声信道传输的。我们为猜测次数的ρ-th时刻作为n的函数的最佳可实现指数增长率提供了一个单字母公式。该公式显示了对噪声造成的惩罚的相当清晰的见解。我们描述了实现最优猜测指数的两种不同的随机化方案。其中一个是完全通用的,因为它独立于源(控制要猜测的向量),通道(破坏猜测)和力矩ρ。有趣的是,结果表明,一般来说,当将最佳猜测指数函数作为通道参数的函数或作为ρ的函数进行检查时,它表现出相变:只要信道距离恒等信道(即干净信道)不太远(在某种意义上精确定义),或者等价地,只要ρ大于某个临界值ρc,那么与无噪声猜测的情况相比,猜测指数中就没有任何惩罚。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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