Identifying Almost Sorted Permutations from TCP Buffer Dynamics

Gabriel Istrate
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引用次数: 0

Abstract

Associate to each sequence $A$ of integers (intending to represent packet IDs) a sequence of positive integers of the same length ${\mathcal M}(A)$. The $i$'th entry of ${\mathcal M}(A)$ is the size (at time $i$) of the smallest buffer needed to hold out-of-order packets, where space is accounted for unreceived packets as well. Call two sequences $A$, $B$ {\em equivalent} (written $A\equiv_{FB} B$) if ${\mathcal M}(A)={\mathcal M}(B)$. We prove the following result: any two permutations $A,B$ of the same length with $SUS(A)$, $SUS(B)\leq 3$ (where SUS is the {\em shuffled-up-sequences} reordering measure), and such that $A\equiv_{FB} B$ are identical. The result (which is no longer valid if we replace the upper bound 3 by 4) was motivated by RESTORED, a receiver-oriented model of network traffic we have previously introduced.
从TCP缓冲区动态中识别几乎排序的排列
与每个整数序列$A$(打算表示数据包id)关联一个相同长度的正整数序列${\mathcal M}(A)$。${\mathcal M}(A)$的$i$ ' s条目是保存乱序数据包所需的最小缓冲区的大小(在$i$时间),其中的空间也用于未接收的数据包。如果${\mathcal M}(A)={\mathcal M}(B)$,调用两个序列$A$, {\em}$B$等效(写为$A\equiv_{FB} B$)。我们证明了以下结果:任意两个长度相同的排列$A,B$与$SUS(A)$, $SUS(B)\leq 3$(其中SUS是{\em打乱后的序列}重排序度量),并且$A\equiv_{FB} B$是相同的。结果(如果我们将上限3替换为4,则不再有效)是由我们之前介绍的面向接收器的网络流量模型restore驱动的。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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