Identifying an Honest EXP^NP Oracle Among Many

Shuichi Hirahara
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引用次数: 10

Abstract

We provide a general framework to remove short advice by formulating the following computational task for a function f : given two oracles at least one of which is honest (i.e. correctly computes f on all inputs) as well as an input, the task is to compute f on the input with the help of the oracles by a probabilistic polynomial-time machine, which we shall call a selector. We characterize the languages for which short advice can be removed by the notion of selector: a paddable language has a selector if and only if short advice of a probabilistic machine that accepts the language can be removed under any relativized world. Previously, instance checkers have served as a useful tool to remove short advice of probabilistic computation. We indicate that existence of instance checkers is a property stronger than that of removing short advice: although no instance checker for EXPNP-complete languages exists unless EXPNP = NEXP, we prove that there exists a selector for any EXPNP-complete language, by building on the proof of MIP = NEXP by Babai, Fortnow, and Lund (1991).
在众多Oracle中识别诚实的EXP^NP Oracle
我们提供了一个通用框架,通过为函数f制定以下计算任务来删除简短的建议:给定两个预言机,其中至少一个是诚实的(即正确计算所有输入上的f)以及一个输入,任务是通过概率多项式时间机器在预言机的帮助下计算输入上的f,我们将其称为选择器。我们通过选择器的概念来描述可以删除短通知的语言:当且仅当在任何相对化的世界中可以删除接受该语言的概率机器的短通知时,可填充语言具有选择器。以前,实例检查器是一种有用的工具,用于删除概率计算的简短通知。我们指出实例检查器的存在是一个比删除短通知更强的属性:尽管除非EXPNP = NEXP,否则不存在EXPNP完备语言的实例检查器,但我们证明了存在任何EXPNP完备语言的选择器,通过建立Babai, Fortnow和Lund(1991)对MIP = NEXP的证明。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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