On adaptive (functional MSR code based) distributed storage systems

B. K. Rai
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引用次数: 4

Abstract

Suppose that a data storage service provider implements a functional MSR code based distributed storage system (DSS). Consider a scenario where the service provider has implemented an (n1, k1, B, d1, t1) functional MSR code based DSS, where B is the file that is stored. At a later point of time, due to certain considerations (such as storage cost, download bandwidth to repair failed nodes etc.), the service provider wants to convert this (n1, k1, B, d1, t1) functional MSR code based DSS to an (n2, k2, B, d2, t2) functional MSR code based DSS. The service provider wants to perform this conversion at the lowest possible cost, i.e., by downloading the minimum amount of data. The question is: How should one design an (n1, k1, B, d1, t1) functional MSR code based DSS so that it requires minimum download to convert the DSS to an (n2, k2, B, d2, t2) functional MSR code based DSS? In this paper, we propose a coding scheme which requires the minimum download while converting an (n1, k1, B, d1, t1) functional MSR code based DSS to an (n2, k2, B, d2, t2) functional MSR code based DSS.
基于功能MSR代码的自适应分布式存储系统
假设数据存储服务提供商实现了一个基于MSR代码的分布式存储系统(DSS)。考虑这样一个场景:服务提供者实现了一个基于DSS的(n1, k1, B, d1, t1)功能性MSR代码,其中B是存储的文件。在稍后的时间点,由于某些考虑(例如存储成本,修复故障节点的下载带宽等),服务提供商希望将这个(n1, k1, B, d1, t1)基于功能MSR代码的DSS转换为(n2, k2, B, d2, t2)基于功能MSR代码的DSS。服务提供商希望以尽可能低的成本执行此转换,即通过下载最少的数据量。问题是:如何设计一个基于(n1, k1, B, d1, t1)功能MSR代码的DSS,以便将DSS转换为基于(n2, k2, B, d2, t2)功能MSR代码的DSS需要最少的下载?本文提出了一种将基于(n1, k1, B, d1, t1)功能MSR码的DSS转换为基于(n2, k2, B, d2, t2)功能MSR码的DSS所需下载最少的编码方案。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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