{"title":"Solutions to Diophantine Equations","authors":"","doi":"10.2307/j.ctv131bw89.9","DOIUrl":null,"url":null,"abstract":". In this article, we investigate the solutions of the Diophantine equations p x + ( p + 1) y + ( p + 2) z = M 2 for primes p ≥ 2 when 1 ≤ x , y , z ≤ 2. We establish : (i) When p = 2 and x = y = z = 1, the equation has a unique solution. (ii) When p = 4 N + 1 and 1 ≤ x , y , z ≤ 2, the equations have no solutions. (iii) When p = 4 N + 3 and x = y = z = 1, the equation has infinitely many solutions. (iv) When 3 ≤ p ≤ 199 and x = 1, y = z = 2, the equation has exactly one solution. (v) In all other cases 1 ≤ x , y , z ≤ 2 which are not mentioned above, the equations have no solutions.","PeriodicalId":281730,"journal":{"name":"An Invitation to Modern Number Theory","volume":"76 1","pages":"0"},"PeriodicalIF":0.0000,"publicationDate":"2020-07-21","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":null,"platform":"Semanticscholar","paperid":null,"PeriodicalName":"An Invitation to Modern Number Theory","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.2307/j.ctv131bw89.9","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 0
Abstract
. In this article, we investigate the solutions of the Diophantine equations p x + ( p + 1) y + ( p + 2) z = M 2 for primes p ≥ 2 when 1 ≤ x , y , z ≤ 2. We establish : (i) When p = 2 and x = y = z = 1, the equation has a unique solution. (ii) When p = 4 N + 1 and 1 ≤ x , y , z ≤ 2, the equations have no solutions. (iii) When p = 4 N + 3 and x = y = z = 1, the equation has infinitely many solutions. (iv) When 3 ≤ p ≤ 199 and x = 1, y = z = 2, the equation has exactly one solution. (v) In all other cases 1 ≤ x , y , z ≤ 2 which are not mentioned above, the equations have no solutions.
. 本文研究了当1≤x, y, z≤2时,当质数p≥2时,Diophantine方程p x + (p + 1) y + (p + 2) z = m2的解。我们建立:(i)当p = 2且x = y = z = 1时,方程有唯一解。(ii)当p = 4n + 1且1≤x, y, z≤2时,方程无解。(iii)当p = 4 N + 3, x = y = z = 1时,方程有无穷多个解。(iv)当3≤p≤199,x = 1, y = z = 2时,方程只有一个解。(v)除上述情况外,1≤x, y, z≤2时,方程无解。