A duality between clause width and clause density for SAT

Chris Calabro, R. Impagliazzo, R. Paturi
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引用次数: 130

Abstract

We consider the relationship between the complexities of k-SAT and those of SAT restricted to formulas of constant density. Let sk be the infimum of those c ges 0 such that k-SAT on n variables can be decided in time O(2cn) and dDelta be the infimum of those c ges 0 such that SAT on n variables and les Deltan clauses can be decided in time O(2cn). We show that limkrarrinfin sk = limDeltararrinfindDelta. So, for any epsi > 0, k-SAT can be solved in 2(1-epsi)n time independent of k if and only if the same is true for SAT with any fixed density of clauses to variables. We derive some interesting consequences from this. For example, assuming that 3-SAT is exponentially hard (that is, s3 > 0), SAT of any fixed density can be solved in time whose exponent is strictly less than that for general SAT. We also give an improvement to the sparsification lemma of Impagliazzo et al. (1998) showing that instances of k-SAT of density slightly more than exponential in k are almost the hardest instances of k-SAT. The previous result showed this for densities doubly exponential in k
SAT分句宽度和分句密度的对偶性
我们考虑了k-SAT的复杂性和被限制为等密度公式的SAT的复杂性之间的关系。设sk是这些c的最小值,使得n个变量上的k-SAT能在时间0 (2cn)内确定d是这些c的最小值使得n个变量上的k-SAT能在时间0 (2cn)内确定。我们证明了limkrarrinfinsk = limDeltararrinfindDelta。因此,对于任何epsi > 0, k-SAT可以在与k无关的2(1-epsi)n时间内求解,当且仅当对于具有任意固定密度的子句到变量的SAT也是如此。我们从中得出了一些有趣的结论。例如,假设3-SAT是指数困难的(即s3 > 0),则任何固定密度的SAT都可以及时求解,其指数严格小于一般SAT。我们还对Impagliazzo等人(1998)的稀疏化引理进行了改进,表明k密度略大于指数的k-SAT实例几乎是k-SAT最难的实例。之前的结果表明密度在k上是双指数的
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