The Spanning Trees Formulas in a Class of Double Fixed-Step Loop Networks

T. Atajan, N. Otsuka, Xuerong Yong
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引用次数: 1

Abstract

A double fixed-step loop network, Cp,q, is a digraph on n vertices 0, 1, 2, ..., n − 1 and for each vertex i (0 < i ≤ n − 1), there are exactly two arcs leaving from vertex i to vertices i + p, i + q (mod n). In this paper, we first derive an expression formula of elementary symmetric polynomials as polynomials in sums of powers then, by using this, for any positive integers p, q, n with p < q < n, an explicit formula for counting the number of spanning trees in a class of double fixed-step loop networks with constant or nonconstant jumps. We allso find two classes of networks that share the same number of spanning trees and we, finally, prove that the number of spanning trees can be approximated by a formula which is based on the mth order Fibonacci numbers. In some special cases, our results generate the formulas obtained in [15],[19],[20]. And, compared with the previous work, the advantage is that, for any jumps p, q, the number of spanning trees can be calculated directly, without establishing the recurrence relation of order 2q−1.
一类双固定步长环网的生成树公式
双定步环网络Cp,q是一个有向图,有n个顶点0,1,2,…为每个顶点n−1和我(0 <我≤n−1),有两个弧离开从顶点到顶点我+ p, i + q (mod n)。在这篇文章中,我们首先推导公式表达式中多项式的初等对称多项式的权力,利用这一点,任何正整数p, q, n和p < < n,显式公式计算生成树的数量在一个类双固定步循环网络与常数或非常数的跳跃。我们也找到了两类共享相同数量的生成树的网络,并最终证明了生成树的数量可以用一个基于m阶斐波那契数的公式来近似。在某些特殊情况下,我们的结果生成[15]、[19]、[20]中得到的公式。与以往的工作相比,其优点在于,对于任意跳跃p, q,都可以直接计算生成树的个数,而不需要建立2q−1阶的递归关系。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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