Compressing as well as the best tiling of an image

Wee Sun Lee
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引用次数: 1

Abstract

We investigate the task of compressing an image by using different probability models for compressing different regions of the image. We introduce a class of probability models for images, the k-rectangular tilings of an image, that is formed by partitioning the image into k rectangular regions and generating the coefficients within each region by using a probability model selected from a finite class of N probability models. For an image of size n/spl times/n, we give a sequential probability assignment algorithm that codes the image with a code length which is within O(k log Nn/k) of the code length produced by the best probability model in the class. The algorithm has a computational complexity of O(Nn/sup 3/). An interesting subclass of the class of k-rectangular tilings is the class of tilings using rectangles whose widths are powers of two. This class is far more flexible than quadtrees and yet has a sequential probability assignment algorithm that produces a code length that is within O(k log Nn/k) of the best model in the class with a computational complexity of O(Nn/sup 2/ log n) (similar to the computational complexity of sequential probability assignment using quadtrees).
压缩以及图像的最佳平铺
我们通过使用不同的概率模型来压缩图像的不同区域来研究压缩图像的任务。我们引入了一类图像的概率模型,即图像的k个矩形切片,它是通过将图像划分为k个矩形区域并使用从有限类N个概率模型中选择的概率模型在每个区域内生成系数而形成的。对于大小为n/spl * /n的图像,我们给出了一种顺序概率分配算法,该算法对图像进行编码,编码长度在该类中最佳概率模型产生的代码长度的O(k log Nn/k)以内。该算法的计算复杂度为0 (Nn/sup /)。k-矩形平铺类的一个有趣的子类是使用宽度为2的幂的矩形的平铺类。这个类比四叉树灵活得多,并且有一个顺序概率分配算法,它产生的代码长度在该类中最佳模型的O(k log Nn/k)以内,计算复杂度为O(Nn/sup 2/ log n)(类似于使用四叉树的顺序概率分配的计算复杂度)。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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