Gold-dppm-Arylazoimidazole Complexes: Synthesis, Spectra, and Redox Study

Srx Chemistry Pub Date : 1900-01-01 DOI:10.3814/2010/424392
P. Byabartta
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Abstract

[Ag(tht)(OTf)]-assisted reaction produces [ Au III ( dppm ) ( tht ) 2 ] ( OSO 2 CF 3 ) 2 , reacts with R a a i R ′ in dichloromethane medium followed by ligand addition, and leads to [ Au III ( dppm ) ( R a a i R ′ ) ] ( OTf ) 2 ( R a a i R ′ = p –R–C 6 H 4 –N = N–C 3 H 2 –NN–1– R ′ , (1–3), abbreviated as N, N ′ -chelator, where N(imidazole) and N(azo) represent N and N ′ , resp.; R = H (a), Me (b), Cl (c) and R ′ = Me (1), CH 2 CH 3 (2), CH 2 Ph (3), dppm is diphenylphosphinomethane, OSO 2 CF 3 is the triflate anion, and tht is tetrahydrothiophen). Ir spectra of the complexes show –C=N– and –N=N– stretching near at 1590 and 1370 cm − 1 and near at 1100, 755, 695, 545, and 505 cm − 1 due to the presence of dppm. The H 1 NMR spectral measurements suggest that methylene, – CH 2 –, in RaaiEt gives a complex AB type multiplet while in Raai CH 2 Ph it shows AB type quartets. Electrochemistry assigns ligand reduction.
金-dppm-芳唑咪唑配合物:合成、光谱及氧化还原研究
[Ag(阻)(传递)]资助建设反应产生(非盟III (dppm)(阻)2](OSO 2 CF 3) 2,与我一个R反应的二氯甲烷中紧随其后的是配体,并导致(Au三世(dppm) (R ir)](传递)2(一个我R ' = p R c 6 H 4 - N = c 3 H 2 -NN-1 - R的,(1 - 3),缩写为N, N的螯合剂,其中N(咪唑)和N(偶氮)代表N, N’,分别地;R = H (a), Me (b), Cl (c)和R ' = Me (1), ch2 ch3 (2), ch2 Ph (3), dppm是二苯基膦甲烷,oso2 cf3是三酸盐阴离子,这是四氢噻吩)。配合物的红外光谱显示,由于dppm的存在,c =N -和- N=N -在1590和1370 cm−1附近以及在1100、755、695、545和505 cm−1附近伸展。氢核磁共振谱测量表明,亚甲基- ch2 -在RaaiEt中呈现AB型复合体,而在raaich2 Ph中呈现AB型复合体。电化学分配配体还原。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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