Scheduling with Many Shared Resources

Max A. Deppert, K. Jansen, M. Maack, Simon Pukrop, M. Rau
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Abstract

Consider the many shared resources scheduling problem where jobs have to be scheduled on identical parallel machines with the goal of minimizing the makespan. However, each job needs exactly one additional shared resource in order to be executed and hence prevents the execution of jobs that need the same resource while being processed. Previously, an approximation ratio of asymptotically 2 was the best known result for this problem. Furthermore, a 6/5-approximation for the case with only two machines was known as well as a PTAS for the case with a constant number of machines. We present a simple and fast 5/3-approximation and a much more involved but still reasonable 1.5-approximation. Furthermore, we provide a PTAS for the case with only a constant number of machines, which is arguably simpler and faster than the previously known one, as well as a PTAS with resource augmentation for the general case. The approximation schemes make use of the N-fold integer programming machinery, which has found more and more applications in the field of scheduling recently. It is plausible that the latter results can be improved and extended to more general cases. Lastly, we give an inapproximability result for the natural problem extension where each job may need up to a constant number of different resources, namely 3, ruling out better than 5/4 approximations for that case.
使用多个共享资源调度
考虑许多共享资源调度问题,其中作业必须在相同的并行机器上调度,目标是最小化完工时间。但是,每个作业需要一个额外的共享资源才能执行,因此可以防止在处理过程中需要相同资源的作业执行。以前,对于这个问题,最著名的结果是渐近的近似比为2。此外,对于只有两台机器的情况,已知6/5近似,对于机器数量恒定的情况,也知道PTAS。我们提出了一个简单而快速的5/3近似值和一个更复杂但仍然合理的1.5近似值。此外,我们为只有恒定数量的机器的情况提供了一个PTAS,这可以说比以前已知的情况更简单和更快,并且为一般情况提供了一个具有资源增强的PTAS。该逼近方案利用了n重整数规划机制,近年来在调度领域得到了越来越多的应用。后一种结果可以改进并推广到更一般的情况,这似乎是合理的。最后,我们给出了自然问题扩展的不可逼近性结果,其中每个作业可能需要多达常数个不同的资源,即3个,排除了这种情况下优于5/4的近似。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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