Deactivation and reaction of excited states of Rb in collisions with H2, CH4 and C2H6

SPIE LASE Pub Date : 2016-04-22 DOI:10.1117/12.2218119
V. Azyazov, A. P. Torbin, A. Mebel, S. Bresler, M. Heaven
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引用次数: 1

Abstract

Alkali vapor lasers commonly use methane (CH4) or ethane (C2H6) to induce energy transfer between the optically pumped level (n2P3/2) and the upper laser level (n2P1/2). A complication is that the alkali metal eventually reacts with the hydrocarbons. The reaction becomes exothermic for alkali atoms that have been excited by energy pooling processes such as Rb(5p)+Rb(5p)→Rb(*)+Rb(5s), where * indicates 6s, 6p or 4d. We have used laser pump-probe methods to examine the reactions of Rb(n2P) with CH4, and C2H6 for states with n=6 and 7. Pump-probe measurements indicated a loss of Rb due to a reaction. Surprisingly, the RbH product was not detected with CH4, and C2H6. High-level ab initio calculations have been used to study the reactive interactions between Rb, methane and ethane.
Rb与H2、CH4和C2H6碰撞时激发态的失活和反应
碱蒸汽激光器通常使用甲烷(CH4)或乙烷(C2H6)来诱导光泵浦能级(n2P3/2)和上层激光能级(n2P1/2)之间的能量转移。一个复杂的问题是,碱金属最终会与碳氢化合物发生反应。对于通过能量池过程激发的碱原子,如Rb(5p)+Rb(5p)→Rb(*)+Rb(5s),反应变成放热的,其中*表示6s, 6p或4d。我们用激光泵浦探针方法研究了Rb(n2P)与CH4和C2H6在n=6和7状态下的反应。泵探针测量表明Rb的损失是由于一个反应。令人惊讶的是,RbH产物没有被CH4和C2H6检测到。用高阶从头计算方法研究了Rb、甲烷和乙烷之间的反应相互作用。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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