金属络合物。第二部分。铜盐与某些四齿甲酸盐的反应

R. Price
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引用次数: 5

摘要

1,5-二-(2-羟基苯基)-和1-(2-羟基苯基)-5-(2-羧基苯基)-3取代的甲氮杂与醋酸铜和氯化亚铜在甲醇中反应生成方形平面铜(II)配合物。相比之下,在类似条件下,1,5-二-(2-羧基苯基)-3取代的甲酸甲烷得到含有两分子水的铜(II)配合物,可能是八面体。氯化铜在甲醇中会发生两个相互竞争的反应,形成金属络合物和将甲醛氧化为四氮唑盐。这些反应的相对重要性是由甲酸甲酯上的取代基决定的。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Metal complex formazans. Part II. The reaction of copper salts with certain tetradentate formazans
1,5-Di-(2-hydroxyphenyl)- and 1-(2-hydroxyphenyl)-5-(2-carboxyphenyl)-3-substituted formazans react with both cupric acetate and cuprous chloride in methanol to give square planar copper(II) complexes. In contrast, under comparable conditions, 1,5-di-(2-carboxyphenyl)-3-substituted formazans give copper(II) complexes containing two molecules of water, which are probably octahedral. With cupric chloride in methanol two competing reactions occur, metal complex formation and oxidation of the formazan to tetrazolium salt. The relative importance of these reactions is governed by the substituents on the formazan.
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