勘误:“通过非均匀通道的蠕动输运的整体动力学和分岔分析”(ASME J. Comput)。非线性力学。， 2022, 17(6)， p. 061001)

{"title":"勘误:“通过非均匀通道的蠕动输运的整体动力学和分岔分析”(ASME J. Comput)。非线性力学。， 2022, 17(6)， p. 061001)","authors":"H. A. Hosham, N. M. Hafez","doi":"10.1115/1.4056592","DOIUrl":null,"url":null,"abstract":"","PeriodicalId":54858,"journal":{"name":"Journal of Computational and Nonlinear Dynamics","volume":"19 1","pages":""},"PeriodicalIF":1.9000,"publicationDate":"2023-01-11","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":"{\"title\":\"Erratum: “Global Dynamics and Bifurcation Analysis for the Peristaltic Transport Through Nonuniform Channels” (ASME J. Comput. Nonlinear Dynam., 2022, 17(6), p. 061001)\",\"authors\":\"H. A. Hosham, N. M. Hafez\",\"doi\":\"10.1115/1.4056592\",\"DOIUrl\":null,\"url\":null,\"abstract\":\"\",\"PeriodicalId\":54858,\"journal\":{\"name\":\"Journal of Computational and Nonlinear Dynamics\",\"volume\":\"19 1\",\"pages\":\"\"},\"PeriodicalIF\":1.9000,\"publicationDate\":\"2023-01-11\",\"publicationTypes\":\"Journal Article\",\"fieldsOfStudy\":null,\"isOpenAccess\":false,\"openAccessPdf\":\"\",\"citationCount\":\"0\",\"resultStr\":null,\"platform\":\"Semanticscholar\",\"paperid\":null,\"PeriodicalName\":\"Journal of Computational and Nonlinear Dynamics\",\"FirstCategoryId\":\"5\",\"ListUrlMain\":\"https://doi.org/10.1115/1.4056592\",\"RegionNum\":4,\"RegionCategory\":\"工程技术\",\"ArticlePicture\":[],\"TitleCN\":null,\"AbstractTextCN\":null,\"PMCID\":null,\"EPubDate\":\"\",\"PubModel\":\"\",\"JCR\":\"Q3\",\"JCRName\":\"ENGINEERING, MECHANICAL\",\"Score\":null,\"Total\":0}","platform":"Semanticscholar","paperid":null,"PeriodicalName":"Journal of Computational and Nonlinear Dynamics","FirstCategoryId":"5","ListUrlMain":"https://doi.org/10.1115/1.4056592","RegionNum":4,"RegionCategory":"工程技术","ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"Q3","JCRName":"ENGINEERING, MECHANICAL","Score":null,"Total":0}