双(1,10-菲罗啉-5,6-二酮)铑(I)六氟磷酸,[Rh(苯-二酮)2]PF6的合成与晶体结构

S. R. Hosseinian, S. Fatemi, H. Hadadzadeh, M. Weil, A. D. Khalaji
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引用次数: 3

摘要

标题化合物[Rh(苯-二酮)2]PF6,其中苯-二酮是1,10-菲罗啉-5,6-二酮,在单斜空间群P21/c (no. 2)中结晶。a = 9.5859(4) a, b = 17.6272(8) a, c = 13.5252(6) a, β = 91.025(1)°,V = 2285.02(17)A3, Z = 4, T = 100 K, R(F) = 0.0329, wR(F2) = 0.0894。Rh(I)原子的配位多面体是以两个独立的苯二酮为配体的畸变[RhN4]双酚体。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Synthesis and Crystal Structure of Bis(1,10-phenanthroline-5,6-dione)rhodium(I) Hexafluorophosphate, [Rh(phen-dione)2]PF6
The title compound, [Rh(phen-dione)2]PF6, where phen-dione is 1,10-phenanthroline-5,6-dione, crystallizes in the monoclinic space group P21/c (no. 14), with a = 9.5859(4)A, b = 17.6272(8)A, c = 13.5252(6)A, β = 91.025(1)°, V = 2285.02(17)A3, Z = 4, T = 100 K, R(F) = 0.0329, wR(F2) = 0.0894. The coordination polyhedron about the Rh(I) atom is a distorted [RhN4] bisphenoid with two independent phen-dione as ligands.
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