关于指数丢番图方程(A^2n)^x+(B^2n)^y=(A^2+B^2)n)^z的注释

Pub Date : 2020-12-23 DOI:10.3336/gm.55.2.03
M. Le, G. Soydan
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引用次数: 1

摘要

设A,B为正整数,使得min{A,B}>1, gcd(A,B) = 1和2|B。利用R. Scott和R. Styer的三元纯指数Diophantine方程解的上界,证明了对于任意正整数n,如果A >B3/8,则方程(A2 n)x + (B2 n)y = (A2 + B2)n)z不存在正整数解(x,y,z)且x > z > y;如果B>A3/6,那么它不存在解(x,y,z)且y>z>x。因此,结合上述结论和已有的一些结果,我们可以推导出,对于任意正整数n,若B≡2 (mod 4)且A >B3/8,则该方程只有正整数解(x,y,z)=(1,1,1)。
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A note on the exponential Diophantine equation (A^2n)^x+(B^2n)^y=((A^2+B^2)n)^z
Let A, B be positive integers such that min{A,B}>1, gcd(A,B) = 1 and 2|B. In this paper, using an upper bound for solutions of ternary purely exponential Diophantine equations due to R. Scott and R. Styer, we prove that, for any positive integer n, if A >B3/8, then the equation (A2 n)x + (B2 n)y = ((A2 + B2)n)z has no positive integer solutions (x,y,z) with x > z > y; if B>A3/6, then it has no solutions (x,y,z) with y>z>x. Thus, combining the above conclusion with some existing results, we can deduce that, for any positive integer n, if B ≡ 2 (mod 4) and A >B3/8, then this equation has only the positive integer solution (x,y,z)=(1,1,1).
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