沙漏形试件屈曲力的预测

IF 3.4 Q2 MATERIALS SCIENCE, MULTIDISCIPLINARY
Ragnar Gjengedal, Ørjan Fyllingen, Vojtech Heinik
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引用次数: 0

摘要

在低周疲劳试验中避免屈曲是非常重要的。屈曲载荷取决于试样形状、材料特性和试验机。在沙漏形试样的研究中,考察了直径对曲率半径的重要性。直径为5和7毫米时,曲率半径与直径的比值分别为4,6和8。所使用的机器是一台带有细长杆的英斯特朗8800,用于气候室。这导致在压缩测试期间机器的刚度降低。建立了有限元模型(在Abaqus中)来确定临界屈曲力。对于沙漏形试件,屈曲意味着侧向运动的开始,而传统欧拉屈曲的典型特征是施加的载荷没有下降。通过对引力计和称重传感器数据的分析,确定了横向运动的起始点。该模型经实验验证,拟合范围在0.6 ~ ?11%取决于试样直径和直径与曲率半径的比值。直径为7mm的试样偏差最小,偏差范围为0.6 ~ ?模型与实验差3.3%。目前的研究是用市售的热轧结构钢筋- 16毫米完成的。
本文章由计算机程序翻译,如有差异,请以英文原文为准。

Prediction of buckling force in hourglass-shaped specimens

Prediction of buckling force in hourglass-shaped specimens

It is important to avoid buckling during low-cycle fatigue testing. The buckling load is dependent on the specimen shape, material properties, and the testing machine. In the present investigation of hourglass-shaped specimens the importance of the diameter to radius of curvature is examined. Diameters of 5 and 7 mm are examined with a ratio of radius of curvature to diameter of 4, 6, and 8. The machine used is an Instron 8800 with elongated rods for a climate chamber. This leads to a reduced stiffness of the machine during compression testing. A finite element model (in Abaqus) is developed to identify the critical buckling force. For hourglass-shaped specimens, buckling means onset of sideways movement, without a drop in the applied load which is typical for conventional Euler buckling. The onset of sideways movement is identified experimentally by analysis of the data from extensometer and the load cell. This model is verified by experiments and fits within 0.6 to ? 11% depending on the specimen diameter and diameter to radius of curvature ratio. The smallest deviations are obtained for the 7-mm-diameter specimen with deviation varying from 0.6 to ? 3.3% between the model and the experiments. The current investigation is done with a commercially available hot rolled structural steel bar of ?16 mm.

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来源期刊
CiteScore
8.60
自引率
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