关于 $NP$ 与 ${\rm co}NP$

Tianrong Lin
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引用次数: 0

摘要

我们在本文中证明,有一种语言$L_d$被一些非确定性图灵机所接受,但不被任何${\rm co}\mathcal{NP}$机器所接受(定义在后)。我们进一步证明 $L_d$ 在 $\mathcal{NP}$ 中,从而证明 $\mathcal{NP}\neq{rm co}\mathcal{NP}$.本文使用的技术是懒对角化技术和作者在新近的工作中开发的新技术(\cite{Lin21})。作为一个副产品,我们再次得出了 $\mathcal{P}\neq\mathcal{NP}$ 这个重要结果,这一点从上述结果和众所周知的事实 $\mathcal{P}={rmco}\mathcal{P}$ 中可以清楚地看出。我们还总结了其他直接后果。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
On $NP$ versus ${\rm co}NP$
We prove in this paper that there is a language $L_d$ accepted by some nondeterministic Turing machines but not by any ${\rm co}\mathcal{NP}$-machines (defined later). We further show that $L_d$ is in $\mathcal{NP}$, thus proving that $\mathcal{NP}\neq{\rm co}\mathcal{NP}$. The techniques used in this paper are lazy-diagonalization and the novel new technique developed in author's recent work \cite{Lin21}. As a by-product, we reach the important result \cite{Lin21} that $\mathcal{P}\neq\mathcal{NP}$ once again, which is clear from the above outcome and the well-known fact that $\mathcal{P}={\rm co}\mathcal{P}$. Other direct consequences are also summarized.
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