{"title":"超限基数","authors":"J. N. Salunke, B. S. Satpute","doi":"10.1201/9781315273761-36","DOIUrl":null,"url":null,"abstract":"For transfinite cardinal number α, using Zorn’s lemma we have given a simple proof which is understandable to undergraduate students, of the result α + α = αα = α, that is, idempotency for addition and multiplication. Moreover for a cardinal number with 2 ≤ < α we obtain easily α + = α = α, α = α α = 2 α , α < . Using these results we get many results directly as א0 + ∁ = א0∁ = ∁ + ∁ = ∁∁ = ∁, א0 א0 = ∁ = ∁0 = 20 , ∁ = א0 ∁ = 2 where א0 = card N, ∁ = card R. -------------------------------------------------------------------------------------------------------------------------------------Date of Submission: 05-08-2018 Date of acceptance: 22-08-2018 -------------------------------------------------------------------------------------------------------------------------------------","PeriodicalId":348406,"journal":{"name":"Introductory Concepts for Abstract Mathematics","volume":"41 1","pages":"0"},"PeriodicalIF":0.0000,"publicationDate":"2018-10-03","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":"{\"title\":\"Transfinite Cardinal Numbers\",\"authors\":\"J. N. Salunke, B. S. Satpute\",\"doi\":\"10.1201/9781315273761-36\",\"DOIUrl\":null,\"url\":null,\"abstract\":\"For transfinite cardinal number α, using Zorn’s lemma we have given a simple proof which is understandable to undergraduate students, of the result α + α = αα = α, that is, idempotency for addition and multiplication. Moreover for a cardinal number with 2 ≤ < α we obtain easily α + = α = α, α = α α = 2 α , α < . Using these results we get many results directly as א0 + ∁ = א0∁ = ∁ + ∁ = ∁∁ = ∁, א0 א0 = ∁ = ∁0 = 20 , ∁ = א0 ∁ = 2 where א0 = card N, ∁ = card R. -------------------------------------------------------------------------------------------------------------------------------------Date of Submission: 05-08-2018 Date of acceptance: 22-08-2018 -------------------------------------------------------------------------------------------------------------------------------------\",\"PeriodicalId\":348406,\"journal\":{\"name\":\"Introductory Concepts for Abstract Mathematics\",\"volume\":\"41 1\",\"pages\":\"0\"},\"PeriodicalIF\":0.0000,\"publicationDate\":\"2018-10-03\",\"publicationTypes\":\"Journal Article\",\"fieldsOfStudy\":null,\"isOpenAccess\":false,\"openAccessPdf\":\"\",\"citationCount\":\"0\",\"resultStr\":null,\"platform\":\"Semanticscholar\",\"paperid\":null,\"PeriodicalName\":\"Introductory Concepts for Abstract Mathematics\",\"FirstCategoryId\":\"1085\",\"ListUrlMain\":\"https://doi.org/10.1201/9781315273761-36\",\"RegionNum\":0,\"RegionCategory\":null,\"ArticlePicture\":[],\"TitleCN\":null,\"AbstractTextCN\":null,\"PMCID\":null,\"EPubDate\":\"\",\"PubModel\":\"\",\"JCR\":\"\",\"JCRName\":\"\",\"Score\":null,\"Total\":0}","platform":"Semanticscholar","paperid":null,"PeriodicalName":"Introductory Concepts for Abstract Mathematics","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.1201/9781315273761-36","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
引用次数: 0
摘要
For transfinite cardinal numberα、使用佐恩引理we have给定a simple被一本可以证明当时本科学生,of the resultα+α=αα=α,that, idempotency除了和multiplication。tip for a cardinal号码与2≤<我们很容易地获取αα+=α=α,α=αα= 2α,α<。使用这些结果我们get many结果直接+ 0轴א∁=א∁=∁+∁=∁∁=∁,אא0 =∁=∁0 = 20,∁=א∁= 2 whereא0 = N,∁=卡R . ------------------------------------------------------------------------------------------------------------------------------------- 约会或屈服:05-08-2018约会或验收:8 -------------------------------------------------------------------------------------------------------------------------------------
For transfinite cardinal number α, using Zorn’s lemma we have given a simple proof which is understandable to undergraduate students, of the result α + α = αα = α, that is, idempotency for addition and multiplication. Moreover for a cardinal number with 2 ≤ < α we obtain easily α + = α = α, α = α α = 2 α , α < . Using these results we get many results directly as א0 + ∁ = א0∁ = ∁ + ∁ = ∁∁ = ∁, א0 א0 = ∁ = ∁0 = 20 , ∁ = א0 ∁ = 2 where א0 = card N, ∁ = card R. -------------------------------------------------------------------------------------------------------------------------------------Date of Submission: 05-08-2018 Date of acceptance: 22-08-2018 -------------------------------------------------------------------------------------------------------------------------------------