M/G/1的简单近最优调度

Ziv Scully, Mor Harchol-Balter, Alan Scheller-Wolf
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引用次数: 2

摘要

考虑以最小化M/G/1队列平均响应时间为目标的抢占调度问题。当我们知道每个作业的大小时,最短剩余处理时间(SRPT)策略是最优的。不幸的是,在许多情况下,我们无法访问每个作业的大小。相反,我们只知道工作规模的分布。在这种情况下,Gittins策略可以最小化平均响应时间,但其复杂的优先级结构在计算上是难以处理的。gittin的一个更简单的替代方案是最短预期剩余处理时间(SERPT)策略。虽然SERPT是SRPT对未知作业大小的自然扩展,但对于平均响应时间而言,SERPT是否接近最优是未知的。我们提出了一种新的SERPT变体,称为单调SERPT (M-SERPT),它与SERPT一样简单,但在任何作业大小分布的所有负载下都具有接近最佳的平均响应时间。具体来说,我们证明了M-SERPT和Gittins的平均响应时间比在ρ≤8/9时不超过3,在任何负载下不超过5。这使得M-SERPT成为已知的唯一具有平均响应时间常数因子近似比的非gittin调度策略。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Simple Near-Optimal Scheduling for the M/G/1
We consider the problem of preemptively scheduling jobs to minimize mean response time of an M/G/1 queue. When we know each job's size, the shortest remaining processing time (SRPT) policy is optimal. Unfortunately, in many settings we do not have access to each job's size. Instead, we know only the job size distribution. In this setting the Gittins policy is known to minimize mean response time, but its complex priority structure can be computationally intractable. A much simpler alternative to Gittins is the shortest expected remaining processing time (SERPT) policy. While SERPT is a natural extension of SRPT to unknown job sizes, it is unknown whether or not SERPT is close to optimal for mean response time. We present a new variant of SERPT called monotonic SERPT (M-SERPT) which is as simple as SERPT but has provably near-optimal mean response time at all loads for any job size distribution. Specifically, we prove the mean response time ratio between M-SERPT and Gittins is at most 3 for load ρ ≤ 8/9 and at most 5 for any load. This makes M-SERPT the only non-Gittins scheduling policy known to have a constant-factor approximation ratio for mean response time.
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