勒贝格积分定理的另一种证明

B. Josephson
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引用次数: 0

摘要

通过(2),F(x)= \ F '\是a.c。因此30o使得如果{[ar, br)}是一个非重叠区间的Ja有限集,t (b, -ar) O使得如果| br-ar | K(br-ar)。现在如果/交流(ar, br),然后由(1 ), ,)-/(«,) | = 我“f ^ T I / '我= f f (a) | {br)。I Jar Jar emms - h J
本文章由计算机程序翻译,如有差异,请以英文原文为准。
An Alternative Proof of a Theorem on the Lebesgue Integral
By (2), F(x)= \f'\ is a.c. Hence 3<5,>O such that if {[ar, br)} is a Ja finite set of non-overlapping intervals and T.(b, — ar)O such that if | br — ar | <<52, then \Abr)-Kar) | <\E (5) Now take 8 = min^ , S2, I, e/SK), and choose intervals [ar, br] to satisfy (3). The sum Z \f(b^-f{ar) | may be divided into three parts, by putting \ fibr)-f(ar)\ into S, if/isa.c. in [ar, br], Z2 if/is not a.c. in [ar, b,] and \f(br)-f(ar) \^K(br-ar), S3 if/is not a.c. in [ar, br] and \f(br)-f(ar) \>K(br-ar). Now if/is a.c. in [ar, br], then by (1), ,)-/(«,) | = I f"f ^ T I / ' I = I F{br)F(a,) |. I Jar Jar E.M.S.—H J
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