Formally verified Byzantine agreement in presence of link faults

U. Schmid, Bettina Weiss, J. Rushby
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引用次数: 49

Abstract

This paper shows that deterministic consensus in synchronous distributed systems with link faults is possible, despite the impossibility result of Gray (1978). Instead of using randomization, we overcome this impossibility by moderately restricting the inconsistency that link faults may cause system-wide. Relying upon a novel hybrid fault model that provides different classes of faults for both nodes and links, we provide a formally verified proof that the m+1-round Byzantine agreement algorithm OMH (Lincoln and Rushby (1993)) requires n > 2f/sub l//sup s/ + f/sub l//sup r/ + f/sub l//sup ra/ + 2(f/sub a/ + f/sub s/) + f/sub o/ + f/sub m/ + m nodes for transparently masking at most f/sub l//sup s/ broadcast and f/sub l//sup r/ receive link faults (including at most f/sub l//sup ra/ arbitrary ones) per node in each round, in addition to at most f/sub a/, f/sub s/, f/sub o/, f/sub m/ arbitrary, symmetric, omission, and manifest node faults, provided that m /spl ges/ f/sub a/ + f/sub o/ + 1. Our approach to modeling link faults is justified by a number of theoretical results, which include tight lower bounds for the required number of nodes and an analysis of the assumption coverage in systems where links fail independently with some probability p.
在链路故障的情况下正式验证拜占庭协议
本文表明,尽管Gray(1978)给出了不可能的结果,但在链路故障的同步分布式系统中,确定性共识是可能的。我们没有使用随机化,而是通过适度限制链路故障可能导致系统范围内的不一致性来克服这种不可能性。基于一种新型的混合故障模型,该模型为节点和链路提供了不同类型的故障,我们提供一个正式验证证明了m + 1轮拜占庭协议算法OMH(林肯和Rushby(1993))需要n > 2 f /子l / /一口s / + f /子l / /一口r / + f /子l / /呷拉/ + 2 (f /子/ + f /子s /) + f /子o / m + f / m / +节点最多透明屏蔽f /子l / l /一口s /广播和f /子/ /一口r /接收链路故障(包括最多f /子l / /呷拉/任意的)每个节点在每一轮中,除了最多f /子/ f / sub s / f /下标o /, f / m /武断,对称、遗漏和明显节点故障,前提是m /spl为/ f/sub a/ + f/sub o/ + 1。我们对链路故障建模的方法得到了许多理论结果的证明,其中包括所需节点数量的严格下界,以及对链路以一定概率p独立故障的系统中的假设覆盖范围的分析。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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