How to Fit In Another Meeting

R. Klein, D. Nussbaum, J. Sack, Jiehua Yi
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Abstract

We are studying the problem of determining suitable meeting times and locations for a group of participants wishing to schedule a new meeting subject to already scheduled meetings possibly held at a number of different locations. Each participant must be able to reach the new meeting location, attend for the entire duration, and reach the next meeting location on time. In particular, we give a solution to the problem instance where each participant has two scheduled meetings separated by a free time interval. For a geometric model, where n participants can travel along straight paths in the Euclidean plane, we present an O(n log n) algorithm to determine the longest meeting duration and a location suitable to all participants. In a graph-based model, transportation is provided by a geometric network over m nodes and e edges in the plane. Participants can have individual weights. Moreover, there can be k groups of participants, such that only one member of each group must attend the meeting. In this model, a location for a meeting of longest possible duration can be determined in time O(en¿(k) log k + n log n + mn log m), where a (k) denotes the extremely slowly growing inverse Ackermann function.
如何参加另一场会议
我们正在研究为一组与会者确定合适的会议时间和地点的问题,这些与会者希望安排一次新的会议,但不包括可能在若干不同地点举行的已安排的会议。每个与会者必须能够到达新的会议地点,参加整个会议期间,并按时到达下一个会议地点。特别地,我们给出了一个问题实例的解决方案,其中每个参与者都有两个由空闲时间间隔分开的预定会议。对于一个几何模型,其中n个参与者可以沿着欧几里得平面上的直线路径行进,我们提出了一个O(n log n)算法来确定最长的会议持续时间和适合所有参与者的位置。在基于图的模型中,运输是由平面上m个节点和e条边的几何网络提供的。参与者可以有个人的体重。此外,可以有k组参与者,这样每个组中只有一名成员必须参加会议。在该模型中,可以在O(en¿(k) log k + n log n + mn log m)时间内确定可能持续时间最长的会议地点,其中a (k)表示极其缓慢增长的逆Ackermann函数。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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